PepMiniiso/pylibraries/tendo/tests/test_singleton.py

59 lines
1.6 KiB
Python

import logging
from multiprocessing import Process
import sys
from tendo.singleton import SingleInstance, SingleInstanceException
logger = logging.getLogger("tendo.singleton.test")
logger.addHandler(logging.StreamHandler())
logger.setLevel(logging.DEBUG)
def f(name):
tmp = logger.level
logger.setLevel(logging.CRITICAL) # we do not want to see the warning
try:
me2 = SingleInstance(flavor_id=name) # noqa
except SingleInstanceException:
sys.exit(-1)
logger.setLevel(tmp)
pass
def test_1():
me = SingleInstance(flavor_id="test-1")
del me # now the lock should be removed
assert True
def test_2():
p = Process(target=f, args=("test-2",))
p.start()
p.join()
# the called function should succeed
assert p.exitcode == 0, "%s != 0" % p.exitcode
def test_3():
me = SingleInstance(flavor_id="test-3") # noqa -- me should still kept
p = Process(target=f, args=("test-3",))
p.start()
p.join()
# the called function should fail because we already have another
# instance running
assert p.exitcode != 0, "%s != 0 (2nd execution)" % p.exitcode
# note, we return -1 but this translates to 255 meanwhile we'll
# consider that anything different from 0 is good
p = Process(target=f, args=("test-3",))
p.start()
p.join()
# the called function should fail because we already have another
# instance running
assert p.exitcode != 0, "%s != 0 (3rd execution)" % p.exitcode
def test_4():
lockfile = '/tmp/foo.lock'
me = SingleInstance(lockfile=lockfile)
assert me.lockfile == lockfile